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प्रश्न
If the numerator of a fraction is multiplied by 2 and the denominator is reduced by 5 the fraction becomes `6/5`. And, if the denominator is doubled and the numerator is increased by 8, the fraction becomes `2/5`. Find the fraction.
योग
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उत्तर
Given: Let the fraction be `x/y`.
From "numerator × 2, denominator –5 gives `6/5`":
`(2x)/(y - 5) = 6/5`
⇒ 10x = 6(y – 5)
⇒ 10x = 6y – 30
⇒ 5x – 3y = –15
From "numerator +8, denominator × 2 gives `2/5`":
`(x + 8)/(2y) = 2/5`
⇒ 5(x + 8) = 4y
⇒ 5x + 40 = 4y
⇒ 5x – 4y = –40
Subtract the second equation from the first:
(5x – 3y) – (5x – 4y)
= –15 – (–40)
⇒ y = 25
Substitute y = 25 into 5x – 3y = –15:
5x – 75 = –15
⇒ 5x = 60
⇒ x = 12
The fraction is `12/25`.
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