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If the lens material and the surrounding liquid have the same refractive index (\[n_2 = n_1\]), then:

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Question

If the lens material and the surrounding liquid have the same refractive index (\[n_2 = n_1\]), then:

Options

  • the focal length becomes 1 metre

  • \[P = \frac{n_1}{f}\] and the power doubles

  • \[P = 0\], so the lens has no focusing power (becomes invisible)

  • the lens behaves like a concave lens

MCQ
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Solution

When \[n_2 = n_1\], the factor \[(n_2 - n_1)\] becomes zero, so \[P = 0\]. No refraction occurs at the surfaces, the lens has no focusing power, and it becomes invisible in the medium.

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