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Question
If the equation x2 – kx + 1 = 0 has no real roots then
Options
k < –2
k > 2
–2 < k < 2
none of these
MCQ
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Solution
–2 < k < 2
Explanation:
It is given that the equation x2 – kx + 1 = 0 has no real roots.
∴ (b2 – 4ac) < 0
⇒ (–k)2 – 4 × 1 × 1 < 0
⇒ k2 < 4
⇒ –2 < k < 2
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