Question

For what value of k, the equation kx² – 6x – 2 = 0 has real roots?

Options

• `k ≤ (-9)/2`

• `k ≥ (-9)/2`

• k ≤ –2

• None of these

Answer 1

`bb(k ≥ (-9)/2)`

Explanation:

It is given that the roots of the equation (kx² – 6x – 2 = 0) are real 

∴ D ≥ 0 

⇒ (b² – 4ac) ≥ 0 

⇒ (–6)² – 4 × k × (–2) ≥ 0 

⇒ 36 + 8k ≥ 0 

⇒ `k ≥ (-36)/8` 

⇒ `k ≥ (-9)/2`