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If the displacement of a particle at time t is given by S = 2t^3 – 5t^2 + 4t – 3, then its acceleration at time t = 1 is ______. - Mathematics and Statistics

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Question

If the displacement of a particle at time t is given by S = 2t3 – 5t2 + 4t – 3, then its acceleration at time t = 1 is ______.

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Solution

If the displacement of a particle at time t is given by S = 2t3 – 5t2 + 4t – 3, then its acceleration at time t = 1 is 2.

Explanation:

Given displacement:

S = 2t3 – 5t2 + 4t – 3

Step 1: Find velocity (First derivative)

`v = (dS)/(dt)`

v = 6t2 – 10t + 4

Step 2: Find acceleration (Second derivative)

`a = (dv)/(dt)`

a = 12t – 10

Step 3: Find acceleration at t = 1

a = 12(1) – 10

a = 12 – 10

a = 2

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2024-2025 (July) Official Board Paper
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