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प्रश्न
If the displacement of a particle at time t is given by S = 2t3 – 5t2 + 4t – 3, then its acceleration at time t = 1 is ______.
विकल्प
2
8
10
14
MCQ
रिक्त स्थान भरें
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उत्तर
If the displacement of a particle at time t is given by S = 2t3 – 5t2 + 4t – 3, then its acceleration at time t = 1 is 2.
Explanation:
Given displacement:
S = 2t3 – 5t2 + 4t – 3
Step 1: Find velocity (First derivative)
`v = (dS)/(dt)`
v = 6t2 – 10t + 4
Step 2: Find acceleration (Second derivative)
`a = (dv)/(dt)`
a = 12t – 10
Step 3: Find acceleration at t = 1
a = 12(1) – 10
a = 12 – 10
a = 2
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