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If tan 3A - sqrt3 = 0 and 0 ≤ 3A ≤ 90°; the measure of angle A is ______.

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Question

If tan `3A - sqrt3` = 0 and 0 ≤ 3A ≤ 90°; the measure of angle A is ______.

Options

  • 15°

  • 20°

  • 30°

  • 10°

MCQ
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Solution

If tan `3A - sqrt3` = 0 and 0 ≤ 3A ≤ 90°; the measure of angle A is 20°.

Explanation:

Given \[\tan 3A - \sqrt{3} = 0\], we have \[\tan 3A = \sqrt{3}\]. Since \[\tan 60^\circ = \sqrt{3}\], we get 3A = 60°, which gives \[A = \frac{60^\circ}{3} = 20^\circ\].

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Chapter 21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - EXERCISE 21 (C) [Page 322]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
EXERCISE 21 (C) | Q 1. (b) | Page 322
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