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प्रश्न
If tan `3A - sqrt3` = 0 and 0 ≤ 3A ≤ 90°; the measure of angle A is ______.
पर्याय
15°
20°
30°
10°
MCQ
रिकाम्या जागा भरा
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उत्तर
If tan `3A - sqrt3` = 0 and 0 ≤ 3A ≤ 90°; the measure of angle A is 20°.
Explanation:
Given \[\tan 3A - \sqrt{3} = 0\], we have \[\tan 3A = \sqrt{3}\]. Since \[\tan 60^\circ = \sqrt{3}\], we get 3A = 60°, which gives \[A = \frac{60^\circ}{3} = 20^\circ\].
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