Advertisements
Advertisements
Question
If sin θ = cos (θ – 45°), where θ – 45° are acute angles, find the degree measure of θ
Advertisements
Solution
Sin θ = cos (θ – 45°)
Cos θ = cos (90 – θ)
Cos (θ – 45°) = sin (90° - (θ – 45°)) = sin (90 – θ + 45°)
Sin θ(135 – θ)
θ = 135 – θ
2θ = 135
∴ θ = 135°/2
shaalaa.com
Is there an error in this question or solution?
