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If Sin θ = Cos (θ – 45°), Where θ – 45° Are Acute Angles, Find the Degree Measure of θ - Mathematics

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प्रश्न

If sin θ = cos (θ – 45°), where θ – 45° are acute angles, find the degree measure of θ

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उत्तर

Sin θ = cos (θ – 45°)

Cos θ = cos (90 – θ)

Cos (θ – 45°) = sin (90° - (θ – 45°)) = sin (90 – θ + 45°)

Sin θ(135 – θ)

θ = 135 – θ

2θ = 135

∴ θ = 135°/2

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