Question

If potential difference between the two ends of a metallic wire is doubled, drift speed of free electrons in the wire ______.

Options

• Remains same.

• Becomes double.

• Becomes four times

• Becomes half

Answer 1

If potential difference between the two ends of a metallic wire is doubled, drift speed of free electrons in the wire becomes double.

Explanation:

Drift velocity `= v_d = (eVτ)/(ml)`

When V is Potential difference

According to question, V = 2V

Then `v_d = (2eVτ)/(ml)`

= `2v_d`

Hence, drift velocity also becomes double.