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Question
If PA and PB are two tangents to a circle with centre O such that ∠AРВ = 80°. Then, ∠AOP = ?
Options
40°
50°
60°
70°
MCQ
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Solution
50°
Explanation:
The angle between the two tangents equals 180° – ∠AOB, so the central angle ∠AOB = 180° – 80° = 100°.
By symmetry OP bisects ∠AOB, so ∠AOP = `(100^circ)/2` = 50°.
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