Question

If PA and PB are two tangents to a circle with centre O such that ∠AРВ = 80°. Then, ∠AOP = ?

पर्याय

• 40°

• 50°

• 60°

• 70°

Answer 1

50°

Explanation:

The angle between the two tangents equals 180° – ∠AOB, so the central angle ∠AOB = 180° – 80° = 100°.

By symmetry OP bisects ∠AOB, so ∠AOP = `(100^circ)/2` = 50°.