If P + 1 P = 6 ; Find : P 2 + 1 P 2

If `"p" + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`

Sum

`("p" + (1)/"p")^2`

= `"p"^2 + (1)/"p"^2 + 2`

⇒ 36 = `"p"^2 + (1)/"p"^2 + 2`

⇒ `"p"^2 + (1)/"p"^2`
= 36 - 2
= 34.

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Chapter 4: Expansions - Exercise 4.2

Chapter 4 Expansions
Exercise 4.2 | Q 10.1

Write in the expanded form:

(2a - 3b - c)²

If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]

If \[x - \frac{1}{x} = \frac{15}{4}\], then \[x + \frac{1}{x}\] =

\[\frac{( a^2 - b^2 )^3 + ( b^2 - c^2 )^3 + ( c^2 - a^2 )^3}{(a - b )^3 + (b - c )^3 + (c - a )^3} =\]

If 49a² − b = \[\left( 7a + \frac{1}{2} \right) \left( 7a - \frac{1}{2} \right)\] then the value of b is

Find the square of : 3a + 7b

Expand the following:
(x - 3y - 2z)²

Find the squares of the following:
3p - 4q²

If a² - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`

Simplify:
(2x - 4y + 7)(2x + 4y + 7)