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Question
If `"p" + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`
Sum
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Solution
`("p" + (1)/"p")^2`
= `"p"^2 + (1)/"p"^2 + 2`
⇒ 36 = `"p"^2 + (1)/"p"^2 + 2`
⇒ `"p"^2 + (1)/"p"^2`
= 36 - 2
= 34.
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