Advertisements
Advertisements
Question
If m2 = -2 and n = 2; find the values of: 6m-3 + 4n2
Advertisements
Solution
6m-3 + 4n2
m = - 2, n =2
= 6(-2)-3 + 4(2)2
`= 6 xx 1/-2 xx 1/-2 xx 1/-2 + 4 xx 2 xx 2`
`= (-3)/4 + 16`
`= (-3+16 xx4)/4 = (-3 + 64)/4 = 61/4 = 15 1/4`
APPEARS IN
RELATED QUESTIONS
Evaluate: (26)0
Evaluate: (35 x 47 x 58)0
Simplify, giving Solution with positive index
(−y2) (−y3)
Simplify, giving Solution with positive index
(-3)2 (3)3
Simplify, giving Solution with positive index
(- 4x) (-5x2)
Simplify, giving Solution with positive index
(2a3)4 (4a2)2
Simplify, giving Solution with positive index
`((5"x"^7)^3 . (10"x"^2)^2)/(2"x"^6)^7 = (5^3 "x"^(7xx3) . 10^2 . "x"^(2xx2))/(2^7. "x"^(6xx7))`
Simplify and express the Solution in the positive exponent form:
`((2^3)^5 xx 5^4)/(4^3 xx 5^2)`
Simplify and express the Solution in the positive exponent form:
`- 128/2187`
If m2 = -2 and n = 2; find the values of: 2n3 – 3m
