Evaluate: (26)0

Evaluate: (2⁶)⁰

Sum

(2⁶)⁰ = 2^{(6 ×} ⁰⁾ = 2⁰ = 1

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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)

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Chapter 5: Exponents (Including Laws of Exponents) - Exercise 5 (B)

Chapter 5 Exponents (Including Laws of Exponents)
Exercise 5 (B) | Q 2.3

Evaluate: 8³ x 8^-5 x 8⁴

Evaluate: 5⁴ ÷ 5³ x 5⁵

Evaluate: (3⁵ x 4⁷ x 5⁸)⁰

Simplify, giving Solution with positive index

x²y³. 6x⁵y. 9x³y⁴

Simplify, giving Solution with positive index

`((5"x"^7)^3 . (10"x"^2)^2)/(2"x"^6)^7 = (5^3 "x"^(7xx3) . 10^2 . "x"^(2xx2))/(2^7. "x"^(6xx7))`

Simplify and express the Solution in the positive exponent form:

`((-3)^3 xx 2^6)/(6 xx 2^3)`

Simplify and express the Solution in the positive exponent form:

`((2^3)^5 xx 5^4)/(4^3 xx 5^2)`

Simplify and express the Solution in the positive exponent form:

`- 128/2187`

Evaluate: `5^"n" xx 25^("n" - 1) div (5^("n" -1) xx 25^("n" - 1))`

If m = -2 and n = 2; find the values of m² + n² - 2mn.