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Question
Simplify, giving Solution with positive index
4x2y2 ÷ 9x3y3
Sum
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Solution
4x2y2 ÷ 9x3y3
`= (4"x"^2"y"^2)/(9"x"^3"y"^3) = (4"x"^(2-3) y^(2-3))/9`
`= (4"x"^(-1)"y"^(-1))/9 = 4/(9"xy")` (Since index should by positive)
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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)
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