Question

If in nuclear fission of a piece of uranium, 0.6 g mass is lost, how much energy (in kW h) is obtained?

Answer 1

Given Data:

Mass lost (Δm) = 0.6 g = 0.6 × 10⁻³ kg

Speed of light (c) = 3 × 10⁸ m/s

Conversion factor = 1 kW h = 3.6 × 10⁶ J

1. Calculate Energy in Joules (E):

E = Δm × c²

= (0.6 × 10⁻³) × (3 × 10⁸)²

= 0.6 × 10⁻³ × 9 × 10¹⁶

= 5.4 × 10¹³ J

2. Convert Energy to kW h:

E (in kW h) = `(5.4 xx 10^13 J)/(3.6 xx 10^6 J//kW h)`

= 1.5 × 10⁷ kW h

The energy obtained is 1.5 × 10⁷ kW h.