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Determine the amount of energy released (in MeV) due to the loss of mass of 0.5 kg.

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Question

Determine the amount of energy released (in MeV) due to the loss of mass of 0.5 kg.

Numerical
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Solution

Given Data:

Loss of mass (Δm) = 0.5 kg

Speed of light (c) = 3 × 108 m/s

Conversion factor (1 MeV) = 1.6 × 10−13 J

1. Calculate Energy in Joules (E):

Using Einstein's mass-energy equivalence equation:

E = Δm × c2

= 0.5 × (3 × 108)2

= 0.5 × 9 × 1016

= 4.5 × 1016 J

2. Convert Energy to MeV:

E (in MeV) = `(4.5 xx 10^16 J)/(1.6 xx 10^-13 J//MeV)`

= 2.8125 × 1029 MeV

The amount of energy released is 2.8125 × 1029 MeV.

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Chapter 12: Modern Physics - EXERCISE [Page 303]

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Lakhmir Singh Physics [English] Class 10 ICSE
Chapter 12 Modern Physics
EXERCISE | Q 2. | Page 303
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