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Maharashtra State BoardSSC (English Medium) 9th Standard

If cos θ = 1517 then find sin θ. - Geometry

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Question

If cos θ = `15/17` then find sin θ.

Sum
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Solution

sin2θ + cos2θ = 1

⇒ sin2θ + `(15/17)^2 = 1              ...( cos θ = 15/17)`

⇒ sin2θ + `225/289` = 1 

⇒ sin2θ = `1 - 225/289`

⇒ sin2θ = `(289 - 225)/289`

⇒ sin2θ = `64/289` 

⇒ sin θ = `sqrt (64/289)`       ...(Taking square root of both sides)

⇒ sin θ = `8/17`                 

Thus, the value of sin θ is `8/17`.

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Chapter 8: Trigonometry - Practice Set 8.2 [Page 112]

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Balbharati Mathematics 2 [English] Standard 9 Maharashtra State Board
Chapter 8 Trigonometry
Practice Set 8.2 | Q 4. | Page 112
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