Advertisements
Advertisements
Question
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
A + B + C
Advertisements
Solution
Given, A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3
A + B + C = 3x2 – 4x + 1 + 5x2 + 3x – 8 + 4x2 – 7x + 3
On combining the like terms,
= 3x2 + 5x2 + 4x2 – 4x + 3x – 7x + 1 – 8 + 3
= 12x2 – 8x – 4
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(4xy − 9z); (3xy − 16z)
Solve the following equation.
5m − 4 = 1
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
How much is 21a3 – 17a2 less than 89a3 – 64a2 + 6a + 16?
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
Translate the following algebraic expression:
4b – 3
