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Question
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + 2b2 − 3c2
Sum
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Solution
a2 + 2b2 − 3c2
= 32 + 2 × 02 − 3 × 22
= 9 + 0 − 3 × 4
= 9 − 12
= − 3
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