Advertisements
Advertisements
Question
If a = 3, b = 0, c = 2 and d = 1, find the value of 6a − 3b − 4c − 2d
Sum
Advertisements
Solution
6a − 3b − 4c − 2d
= 6 × 3 − 3 × 0 − 4 × 2 − 2 × 1
= 18 − 0 − 8 − 2
= 18 − 10
= 8
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
y × d = .............
Find the value of `"yx"/"z"`, when x = 8, y = 4 and z = 16
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + 2b2 − 3c2
If x = 2, y = 5 and z = 4, find the value of the following:
`(5"x"^4"y"^2"z"^2)/(2"x"^2)`
Evaluate:
(3y + 8y) – 5y
Simplify:
3x + (8x − 5x) − (7x − x)
Simplify:
− (y − x) − (x + y − `overline(2"x"+"y")`)
Simplify:
2 (3a − b) − 5 (a − 3b)
If x = 3, y = 2 and z = 1; find the value of yx
In the context of algebra, what is the primary definition of 'substitution'?
