Advertisements
Advertisements
Question
If x = 2, y = 3 and z = 4, find the value of 3x2 – 4y2 + 2z2.
Sum
Advertisements
Solution
x = 2, y = 3, z = 4
∴ 3x2 − 4y2 + 2z2
= 3 (2)2 − 4 (3)2 + 2 (4)2
= 3 × 4 − 4 × 9 + 2 × 16
= 12 − 36 + 32
= 12 + 23 − 36
= 44 − 36
= 8
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
b + z − d = ....................
Find the value of 3a − 2b, when a = 8 and b = 10
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + 2b2 − 3c2
State true and false:
`(2"x"-4)/("x"+1)` = − 1, when x = 1
Simplify:
`3"x"+(2"x"-overline("x"+2))`
Simplify:
3x − [5y − {6y + 2 (10y − x)}]
Simplify:
`5{"a"^2-"a"("a"-overline("a"-2))}`
Fill in the blank:
2a + b − c = 2a + (.............)
Fill in the blank:
7x + 2z + 4y − 3 = − 3 + 4y + (.............)
Simplify:
3x – 6 {3x – 8 (5x – 10)}
