Advertisements
Advertisements
Question
If 3x + 5y = 11 and xy = 2, find the value of 9x2 + 25y2
Advertisements
Solution
We have:
\[\left( 3x + 5y \right)^2 = \left( 3x \right)^2 + 2\left( 3x \right)\left( 5y \right) + \left( 5y \right)^2 \]
\[ \Rightarrow \left( 3x + 5y \right)^2 = 9 x^2 + 30xy + 25 y^2 \]
\[ \Rightarrow 9 x^2 + 25 y^2 = \left( 3x + 5y \right)^2 - 30xy\]
\[\Rightarrow 9 x^2 + 25 y^2 = {11}^2 - 30 \times 2\] (\[\because\] \[3x + 5y = 11 \text { and } xy = 2\])
\[\Rightarrow 9 x^2 + 25 y^2 = 121 - 60\]
\[ \Rightarrow 9 x^2 + 25 y^2 = 61\]
RELATED QUESTIONS
Factorize 8a3 – 27b3 – 36a2b + 54ab2
Simplify : \[\frac{1 . 2 \times 1 . 2 \times 1 . 2 - 0 . 2 \times 0 . 2 \times 0 . 2}{1 . 2 \times 1 . 2 + 1 . 2 \times 0 . 2 + 0 . 2 \times 0 . 2}\]
Write the value of 483 − 303 − 183.
Separate the constants and variables from the following :
`-7,7+"x",7"x"+"yz",sqrt5,sqrt("xy"),(3"yz")/8,4.5"y"-3"x",`
8 −5, 8 − 5x, 8x −5y × p and 3y2z ÷ 4x
Evaluate: `(1/2 "a" + 1/2 "b") (1/2 "a" - 1/2 "b")`
Divide: 35a3 + 3a2b - 2ab2 by 5a - b
Divide: 6x3 + 5x2 − 21x + 10 by 3x − 2
The area of a rectangular field is 25x2 + 20xy + 3y2 square unit. If its length is 5x + 3y unit, find its breadth, Hence find its perimeter.
Divide: 5x2 - 3x by x
Give an algebraic equation for the following statement:
“The difference between the area and perimeter of a rectangle is 20”.
