Advertisements
Advertisements
Question
Factorize 64a3 +125b3 + 240a2b + 300ab2
Advertisements
Solution
64a3 +125b3 + 240a2b + 300ab2
= (4a)3 + (5b)3 + 3 x (4a)2 x 5b + 3(4a)(5b)2
= (4a + 5b)3 [∵ a3 + b3 + 3a2b + 3ab2 = (a + b)3]
= (4a + 5b)(4a + 5b)(4a + 5b)
∴ 64a3 +125b3 + 240a2b + 300ab2 = (4a + 5b)(4a + 5b)(4a + 5b)
APPEARS IN
RELATED QUESTIONS
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Product of numbers y and z subtracted from 10.
Simplify : \[\frac{1 . 2 \times 1 . 2 \times 1 . 2 - 0 . 2 \times 0 . 2 \times 0 . 2}{1 . 2 \times 1 . 2 + 1 . 2 \times 0 . 2 + 0 . 2 \times 0 . 2}\]
Evaluate: (4x2 - 4x + 1)(2x3 - 3x2 + 2)
Divide: 25x2y by - 5y2
Divide: p2 + 4p + 4 by p + 2
Divide: x2 + 4xy + 4y2 by x + 2y
Divide: 6x3 + 5x2 − 21x + 10 by 3x − 2
Divide: 12a2 + ax - 6x2 by 3a - 2x
The variable in the expression 16x – 7 is __________
The total number of planets of Sun can be denoted by the variable n.
