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प्रश्न
Factorize 64a3 +125b3 + 240a2b + 300ab2
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उत्तर
64a3 +125b3 + 240a2b + 300ab2
= (4a)3 + (5b)3 + 3 x (4a)2 x 5b + 3(4a)(5b)2
= (4a + 5b)3 [∵ a3 + b3 + 3a2b + 3ab2 = (a + b)3]
= (4a + 5b)(4a + 5b)(4a + 5b)
∴ 64a3 +125b3 + 240a2b + 300ab2 = (4a + 5b)(4a + 5b)(4a + 5b)
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