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Question
Factorize the following expressions
64a3 – b3
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Solution
= (4a)3 - b3
= (4a - b)((4a)2 + 4a b + b2) [∵ a3 - b3 = (a - b)(a2 + ab + b2)]
= (4a - b)(16a2 + 4ab + b2)
∴ 64a3 - b3 = (4a - b)(16a2 + 4ab + b2)
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