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If (2p – 1), 7, 3p Are in Ap, Find the Value of P.

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Question

If (2p – 1), 7, 3p are in AP, find the value of p.

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Solution

Let (2p-1) ,7 and 3p be three consecutive terms of an AP.

Then 7 - (2p -1) = 3p -7

⇒ 5 p = 15

⇒ p= 3

∴ When p =3,(2p -1), 7and 3p form three consecutive terms of an AP.

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