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Question
If `sqrt (2/3)` is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
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Solution
For x = `sqrt (2/3)` to be solution of the given quadratic equation it should satisfy the equation
So, substituting x = `sqrt (2/3)` in the given equation, we get
`3(sqrt (2/3))^2 + m(sqrt (2/3)) + 2 = 0`
`\implies 3(2/3) + m(sqrt (2/3)) + 2 = 0`
`\implies m = -4 sqrt (3/2) = -2sqrt6`
∴ `m = -2sqrt6`
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