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Solve the following quadratic equations by factorization: 4x^2 + 4bx – (a^2 – b^2) = 0

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Question

Solve the following quadratic equations by factorization:

4x2 + 4bx – (a2 – b2) = 0

Sum
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Solution

4x2 + 4bx - (a2 - b2) = 0

4x2 + 2(a + b)x - 2(a - b)x - (a2 - b2) = 0

2x(2x + a + b) - (a - b)(2x + a + b) = 0

(2x - (a - b))(2x + a + b) = 0

Therefore,

2x - (a - b) = 0

2x = a - b

`x=(a-b)/2`

or,

2x + a + b = 0

2x = -(a + b)

`x=(-(a+b))/2`

Hence, `x=(a-b)/2` or `x=(-(a+b))/2`.

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Chapter 4: Quadratic Equations - EXERCISE 4.3 [Page 4.16]

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R.D. Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
EXERCISE 4.3 | Q 18. | Page 4.16
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