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If ω(≠1) is a cube root of unity and (1 + ω)7 = A + Bω, then A and B are respectively the numbers ______.

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Question

If ω(≠1) is a cube root of unity and (1 + ω)7 = A + Bω, then A and B are respectively the numbers ______.

Options

  • 0, 1

  • 1, 1

  • 1, 0

  • −1, 1

MCQ
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Solution

If ω(≠1) is a cube root of unity and (1 + ω)7 = A + Bω, then A and B are respectively the numbers 1, 1.

Explanation:

ω is a cube root of unity

⇒ 1 + ω + ω2 = 0

⇒ 1 + ω = – ω2

⇒ (1 + ω)7 = (– ω2)7

= – ω14

= – ω12 × ω2

= – ω2

= 1 + ω

= A + ω.B

A = 1, B = 1

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Chapter 1: Complex Numbers - Miscellaneous Exercise 1.1 [Page 21]

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