Advertisements
Advertisements
Questions
Identify the chiral molecule from the following.
Which of the following is an example of chiral molecule?
Options
1-Bromobutane
1,1-Dibromobutane
2,3-Dibromobutane
2-Bromobutane
Advertisements
Solution
2,3-Dibromobutane and 2-Bromobutane
Explanation:
At first, we need to make the structure of all compounds to say which is chiral or not.
(a)
\[\begin{array}{cc}
\phantom{........}\ce{H}\\
\phantom{........}|\\
\ce{C - C - C - C - Br}\\
\phantom{........}|\\
\phantom{........}\ce{H}
\end{array}\]
(b)
\[\begin{array}{cc}
\phantom{.........}\ce{Br}\\
\phantom{........}|\\
\ce{C - C - C - C - Br}\\
\phantom{........}|\\
\phantom{........}\ce{H}
\end{array}\]
(c)
\[\begin{array}{cc}
\phantom{..}\ce{Br}\phantom{..}\ce{Br}\phantom{}\\
\phantom{}|\phantom{....}|\phantom{}\\
\ce{C - C - C - C}
\end{array}\]
(d)
\[\begin{array}{cc}
\phantom{......}\ce{Br}\\
\phantom{.....}|\\
\ce{C - C - C - C}\\
\phantom{.....}|\\
\phantom{.....}\ce{H}
\end{array}\]
Now, we can see that 2,3-Dibromobutane and 2-Bromobutane has a Chiral carbon (that carbon which has 4 different attachments).
Hence, It's a chiral molecule.
APPEARS IN
RELATED QUESTIONS
Optical activity of a molecule is associated with _______________
Explain optical activity of 2-chlorobutane.
Which of the following shows optical isomerism?
Which among the following compound is not optically active?
Molecules whose mirror image is non-superimposable over them are known as chiral. Which of the following molecules is chiral in nature?
(+) 2-methylbutan-1-ol (-) 2-methylbutan- 1-ol have different values for which property?
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
What is dextrorotatory substance?
Define the following:
Plane polarized light
Define the following:
Chirality
What is a chiral carbon atom?
Identify the chiral molecule from the following.
Identify chiral molecules from the following.
a.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3}\\
|\phantom{.........}\\
\ce{OH}\phantom{.......}
\end{array}\]
b.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH2 - CH3}\\
|\phantom{..}\\
\ce{Br}\phantom{.}
\end{array}\]
c.
\[\begin{array}{cc}
\ce{CH3 - CH2 - CH2 - CH2 - Br}
\end{array}\]
d.
\[\begin{array}{cc}
\ce{CH3 - CH - CH3 - CH3}\\
|\phantom{.........}\\
\ce{CH3}\phantom{.......}
\end{array}\]
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
Identify the chiral molecule from the following:
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Identify the chiral molecule from the following.
Identify the chiral molecule from the following.
Identify chiral molecule/s from the following.
Sucrose in water is dextro-rotatory, [α]D = +66.4°. When boiled with dilute HCI, the solution becomes leavo-rotatory, [α] = −20°. In this process the sucrose molecule breaks into ______.
