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Question
`(i^(4n + 1) -i^(4n - 1))/2` का क्या मान है?
Sum
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Solution
i, क्योंकि `(i^(4n + 1) -i^(4n - 1))/2 = (i^(4n)i - i^(4n)i^-i)/2`
= `(i - 1/i)/2`
= `(i^2 - 1)/(2i)`
= `(-2)/(2i)`
= i
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