Advertisements
Advertisements
Question
How will you find the thickness of a one rupee coin?
Advertisements
Solution
- Determine the pitch, the least count and the zero error of the screw gauge
- Place the coin between the two studs
- Rotate the head until the coin is held firmly but not tightly, with the help of the ratchat
- Note the reading of the pitch scale crossed by the head scale (PSR) and the head scale division that coincides with the pitch scale axis (HSC)
- The width of the coin is given by PSR + CHSR (Corrected HSR). Repeat the experiment for different positions of the coin
- Tabulate the readings
- The average of the last column readings gives the width of the coin
| S.No. | P.S.R
(mm) |
H.S.C
(division) |
CHSC = HSC ± ZC (Division) | CHSR = CHSC x LC (mm) | Total reading = PSR + CHSR (mm) |
| 1. | mean = mm | ||||
| 2. |
Thickness of the coin = …….. mm
APPEARS IN
RELATED QUESTIONS
Name the instrument which can accurately measure the following
The diameter of a needle
Name the instrument which can accurately measure the following
The thickness of a paper
What do you know about pitch of screw gauge?
The precision of the screw gauge is 0.001 cm.
Write the principle of screw gauge.
Write about the positive zero error in the screw gauge instrument.
A screw gauge has pitch 1 mm and 100 circular divisions. Zero error = 8 divisions below. With a wire, 1st main scale is visible and 72nd circular division coincides. Find the wire’s radius.
A screw gauge has a pitch of 1 mm and 100 divisions on the circular scale. What is the least count of the instrument?
The main scale reading of a screw gauge is 2 mm and the circular scale reading is 45. If the least count is 0.01 mm, what is the actual reading?
