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प्रश्न
How will you find the thickness of a one rupee coin?
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उत्तर
- Determine the pitch, the least count and the zero error of the screw gauge
- Place the coin between the two studs
- Rotate the head until the coin is held firmly but not tightly, with the help of the ratchat
- Note the reading of the pitch scale crossed by the head scale (PSR) and the head scale division that coincides with the pitch scale axis (HSC)
- The width of the coin is given by PSR + CHSR (Corrected HSR). Repeat the experiment for different positions of the coin
- Tabulate the readings
- The average of the last column readings gives the width of the coin
| S.No. | P.S.R
(mm) |
H.S.C
(division) |
CHSC = HSC ± ZC (Division) | CHSR = CHSC x LC (mm) | Total reading = PSR + CHSR (mm) |
| 1. | mean = mm | ||||
| 2. |
Thickness of the coin = …….. mm
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संबंधित प्रश्न
Name the instrument which can accurately measure the following
The thickness of a paper
Name the instrument which can accurately measure the following
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Name the instrument which has the least count
0.01 mm
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______ consists of a ‘U’ shape metal frame.
The precision of the screw gauge is 0.001 cm.
Write the principle of screw gauge.
A screw gauge has pitch 1 mm and 100 circular divisions. Zero error = 8 divisions below. With a wire, 1st main scale is visible and 72nd circular division coincides. Find the wire’s radius.
A screw gauge has a pitch of 1 mm and 100 divisions on the circular scale. What is the least count of the instrument?
The main scale reading of a screw gauge is 2 mm and the circular scale reading is 45. If the least count is 0.01 mm, what is the actual reading?
