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प्रश्न
A screw gauge has pitch 1 mm and 100 circular divisions. Zero error = 8 divisions below. With a wire, 1st main scale is visible and 72nd circular division coincides. Find the wire’s radius.
पर्याय
1.64 mm
0.82 mm
1.80 mm
0.90 mm
MCQ
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उत्तर
0.82 mm
Explanation:
Least count = \[\frac {\text {1 mm}}{100}\] = 0.01 mm
Zero error = +8 × L.C = +0.08 mm
True reading (diameter) = (1 mm + 72 × 0.01 mm) - 0.08 mm
= 1.72 mm - 0.08 mm = 1.64 mm
Therefore, radius = \[\frac{\text{diameter}}{2}\] = \[\frac {1.64}{2}\] = 0.82 mm
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Screw Gauge
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