Question

How much heat energy is gained when 0.6 kg of water at 25°C is brought to its boiling point?

[Sp. heat capacity of water = 4200 J kg⁻¹°C⁻¹].

Answer 1

Rise in temperature θ_R = (100 − 25) = 75°C

∴ Heat absorbed by water = mcθ_R

= 0.6 kg × 4200 J kg⁻¹°C⁻¹ × 75°C

= 189000 J