Question

A solid of mass 0.15 kg is heated from 10°C to 90°C. If the specific heat capacity of the solid is 390 J kg⁻¹°C⁻¹, find the heat absorbed by the solid.

Answer 1

Rise in temperature θ_R = (90 − 10) = 80°C

∴ Heat absorbed = mcθ_R

= 0.15 kg × 390 J kg⁻¹°C⁻¹ × 80°C

= 4680 J