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Question
How many numbers of three digits are divisible by 9?
Sum
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Solution
To find the number of terms (n), use the formula for the nth term of an AP:
an = a1 + (n − 1)d
Substitute the values an = 999, a1 = 108, and d = 9:
999 = 108 + (n − 1)9
Subtract 108 from both sides.
999 − 108 = (n − 1)9
⇒ 891 = (n − 1)9
⇒ `891/9 = (n − 1)`
⇒ 99 = (n − 1)
⇒ 99 + 1 = n
⇒ 100 = n
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