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How many numbers of three digits are divisible by 9? - Mathematics

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Question

How many numbers of three digits are divisible by 9?

Sum
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Solution

To find the number of terms (n), use the formula for the nth term of an AP:

an = a1 + (n − 1)d

Substitute the values an = 999, a1 = 108, and d = 9:

999 = 108 + (n − 1)9

Subtract 108 from both sides.

999 − 108 = (n − 1)9

⇒ 891 = (n − 1)9

⇒ `891/9 = (n − 1)`

⇒ 99 = (n − 1)

⇒ 99 + 1 = n

⇒ 100 = n

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Chapter 9: Arithmetic and geometric progression - Exercise 9B [Page 180]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 9 Arithmetic and geometric progression
Exercise 9B | Q 5. (b) | Page 180
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