मराठी

How many numbers of three digits are divisible by 9? - Mathematics

Advertisements
Advertisements

प्रश्न

How many numbers of three digits are divisible by 9?

बेरीज
Advertisements

उत्तर

To find the number of terms (n), use the formula for the nth term of an AP:

an = a1 + (n − 1)d

Substitute the values an = 999, a1 = 108, and d = 9:

999 = 108 + (n − 1)9

Subtract 108 from both sides.

999 − 108 = (n − 1)9

⇒ 891 = (n − 1)9

⇒ `891/9 = (n − 1)`

⇒ 99 = (n − 1)

⇒ 99 + 1 = n

⇒ 100 = n

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Arithmetic and geometric progression - Exercise 9B [पृष्ठ १८०]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 9 Arithmetic and geometric progression
Exercise 9B | Q 5. (b) | पृष्ठ १८०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×