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Given x ∈ {integers}, find the solution set of: –5 ≤ 2x – 3 < x + 2 - Mathematics

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Question

Given x ∈ {integers}, find the solution set of:

–5 ≤ 2x – 3 < x + 2

Sum
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Solution

–5 ≤ 2x – 3 < x + 2

`=>` –5 ≤ 2x – 3 and 2x – 3 < x + 2

`=>` –5 + 3 ≤ 2x and 2x – x < 2 + 3

`=>` –2 ≤ 2x and x < 5

`=>` x ≥ –1 and x < 5

Since x ∈ {integers}

‌∴ Solution set = {–1, 0, 1, 2, 3, 4}

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