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प्रश्न
Given x ∈ {integers}, find the solution set of:
–5 ≤ 2x – 3 < x + 2
योग
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उत्तर
–5 ≤ 2x – 3 < x + 2
`=>` –5 ≤ 2x – 3 and 2x – 3 < x + 2
`=>` –5 + 3 ≤ 2x and 2x – x < 2 + 3
`=>` –2 ≤ 2x and x < 5
`=>` x ≥ –1 and x < 5
Since x ∈ {integers}
∴ Solution set = {–1, 0, 1, 2, 3, 4}
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