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Given x ∈ {whole numbers}, find the solution set of: –1 ≤ 3 + 4x < 23 - Mathematics

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प्रश्न

Given x ∈ {whole numbers}, find the solution set of:

–1 ≤ 3 + 4x < 23

योग
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उत्तर

–1 ≤ 3 + 4x < 23

`\implies` –1 ≤ 3 + 4x and 3 + 4x < 23

`\implies` – 4 ≤ 4x and 4x < 20

`\implies` x ≥ –1 and x < 5

Since, x in {whole numbers}

∴ Solution set = {0, 1, 2, 3, 4}

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