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Question
Given that f(x) = `{{:(sqrt(x - 1), x ≥ 1),(4, x < 1):}` Find f(a + 1) in terms of a. (Given that a ≥ 0)
Sum
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Solution
f(x) = `sqrt(x - 1)`, f(x) = 4
f(a + 1) = `sqrt("a" + 1 - 1)`
= `sqrt("a")`
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Chapter 1: Relations and Functions - Unit Exercise – 1 [Page 33]
