Question

Given that f(x) = `{{:(sqrt(x - 1), x ≥ 1),(4, x < 1):}` Find f(a + 1) in terms of a. (Given that a ≥ 0)

Answer 1

f(x) = `sqrt(x - 1)`, f(x) = 4

f(a + 1) = `sqrt("a" + 1 - 1)`

= `sqrt("a")`