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Question
Given that AB is a straight line. Calculate the value of x° in the following cases
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Solution
Since the angles are linear pair
∠AOC + ∠BOC = 180°
3x° + 42° = 180°
3x° = 180° − 42°
3x° = 138°
x° = `(138^circ)/3` = 46°
x° = 46°
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