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प्रश्न
Given that AB is a straight line. Calculate the value of x° in the following cases
बेरीज
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उत्तर
Since the angles are linear pair
∠AOC + ∠BOC = 180°
3x° + 42° = 180°
3x° = 180° − 42°
3x° = 138°
x° = `(138^circ)/3` = 46°
x° = 46°
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पाठ 5: Geometry - Exercise 5.1 [पृष्ठ ९२]
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संबंधित प्रश्न
In the adjoining figure, name the following pairs of angles.
- Obtuse vertically opposite angles
- Adjacent complementary angles
- Equal supplementary angles
- Unequal supplementary angles
- Adjacent angles that do not form a linear pair
Name the pairs of opposite rays in the figure alongside.
Are the ray PM and PT opposite rays? Give reasons for your answer.
Draw the pairs of angles as described below. If that is not possible, say why.
Complementary angles that are not adjacent.
Draw the pairs of angles as described below. If that is not possible, say why.
Angles in a linear pair which are not supplementary.
If the three angles at a point are in the ratio 1 : 4 : 7, find the value of each angle?
In the given figure, find the value of x
In the following figure, POQ is a line, then a is ______.
Two supplementary angles always form a linear pair.
In the following figure, write, if any, (i) each pair of vertically opposite angles, and (ii) each linear pair.
