Advertisements
Advertisements
प्रश्न
In the following figure, PQ || RS. If ∠1 = (2a + b)° and ∠6 = (3a – b)°, then the measure of ∠2 in terms of b is ______.

पर्याय
(2 + b)°
(3 – b)°
(108 – b)°
(180 – b)°
Advertisements
उत्तर
In the following figure, PQ || RS. If ∠1 = (2a + b)° and ∠6 = (3a – b)°, then the measure of ∠2 in terms of b is (108 – b)°.
Explanation:

Since, PQ || RS and line 1 is a transversal.
∴ ∠2 = ∠6 = (3a – b)° ...(i) [Corresponding angles]
∠1 + ∠2 = 180° ...[Angles on a straight line PQ]
⇒ ∠2 = 180° – (2a + b)° ...(ii) [∵ ∠1 = (2a + b)° (given)]
From (i) and (ii), we have
⇒ (3a – b)° = 180° – (2a + b)°
⇒ 3a – b = 180° – 2a – b
⇒ 3a – b + 2a + b = 180°
⇒ 5a = 180°
⇒ a = `180^circ/5` = 36°
∴ a = 36°
Now, ∠2 – (3a – b)° ...[From (i)]
⇒ ∠2 = (3 × 36° – b)° = (108 – b)°
APPEARS IN
संबंधित प्रश्न
Given that AB is a straight line. Calculate the value of x° in the following cases
The measure of ∠BOC is
Find the value of y
Two angles are in the ratio 11 : 25. If they are linear pair, find the angles
In the following figure, ∠ROS is a right angle and ∠POR and ∠QOS are in the ratio 1 : 5. Then, ∠QOS measures ______.

In the following figure, POQ is a line, then a is ______.

In the following figure, write, if any, (i) each pair of vertically opposite angles, and (ii) each linear pair.

In the following figure, write, if any, (i) each pair of vertically opposite angles, and (ii) each linear pair.

Two angles are making a linear pair. If one of them is one-third of the other, find the angles.
