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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Given P(A) = 0.4 and P(A ∪ B) = 0.7 Find P(B) if P(A/B) = 0.4

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Question

Given P(A) = 0.4 and P(A ∪ B) = 0.7 Find P(B) if P(A/B) = 0.4

Sum
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Solution

P(A) = 0.4

P(A ∪ B) = 0.7

P(A/B) = 0.4

(i.e.,) `("P"("A" ∩ "B"))/("P"("B"))` = 0.4

⇒ P(A ∩ B) = 0.4 [P(B)]    ...........(i)

But we know P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

P(A ∩ B) = P(A) + P(B) – P(A ∪ B)

⇒ P(A ∩ B) = 0.4 + P(B) – 0.7

= P(B) – 0.3   .........(ii)

From (i) and (ii) (Equating R.H.S) we get

0.4 [P(B)] = P(B) – 0.3

0.3 = P(B)(1 – 0.4)

0.6 (P(B)) = 0.3

⇒ P(B) = `0.3/06`

= `3/6`

= 0.5

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Chapter 12: Introduction to probability theory - Exercise 12.3 [Page 259]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 12 Introduction to probability theory
Exercise 12.3 | Q 10. (iii) | Page 259

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